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pthPower


\begin{usage} pthPower~x\\ pthPower!~x \end{usage}


Signature


\begin{params} {\em x} & \% & An element of the ring\\ \end{params}

\begin{retval} Return $x^p$\ where $p$\ is the characteristic of the ring. \end{retval}

\begin{remarks} pthPower!~does not make a copy of $x$, which is therefore modif... ...assigned to the result of the call, as in {\tt x := pthPower!~x}. \end{remarks}

Manuel Bronstein 2000-12-13