adjoint

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adjoint

$\begin{usage} adjoint~L \end{usage}$

Signature

adjoint: % $\to$ %

$\begin{params} {\em L} & \% & A differential operator\\ \end{params}$

$\begin{retval} Returns \begin{displaymath} L^\ast = \sum_{i=0}^n (-1)^i \partial^i a_i \end{displaymath}where $L = \sum_{i=0}^n a_i \partial^i$. \end{retval}$

Manuel Bronstein 2000-12-13