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someFactors


\begin{usage}
someFactors~x
\end{usage}


Signature


\begin{params}
{\em x} & \% & A ring element\\
\end{params}

\begin{retval}
Returns $[x_1,\dots,x_n])$\ such that each $x_i$\ divides $x$\ exactly.
\end{retval}

\begin{remarks}
This function is not meant to use factorization or return a
com...
...nctionalities are available.
It is however meant to be efficient.
\end{remarks}


Manuel Bronstein 2000-12-13