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compose,translate


\begin{usage}
compose(p, q)\\ translate(p, r)
\end{usage}

\begin{params}
{\em p, q} & \% & Polynomials\\
{\em r} & R & Amount to translate\\\end{params}

\begin{retval}
compose(p, q) returns
\begin{displaymath}
p(q) = \sum_{i=0}^n a_...
...= \sum_{i=0}^n a_i x^i$, while translate(p, r) returns $p(x - r)$.
\end{retval}


Manuel Bronstein 2000-12-13