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map


\begin{usage}
map~f\\ map!~f\\ map(f)(p)\\ map!(f)(p)
\end{usage}


Signature


\begin{params}
{\em f} & R $\to$\ R & A map\\
{\em p} & \% & A monomial\\\end{params}

\begin{descr}
map(f)(p) returns $f(a) x^n$\ where $p = a x^n$,
while map(f) ret...
... cases, map!~does not make a copy of $p$\ but modifies it in place.
\end{descr}


Manuel Bronstein 2000-12-13