divDiffProd

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divDiffProd

$\begin{usage} divDiffProd(a1, a2, b1, b2, q) \end{usage}$

Signature

divDiffProd: (%, %, %, %, %) $\to$ %

$\begin{params} {\em a1, a2, b1, b2, q} & \% & Elements of the ring \end{params}$

$\begin{retval} divDiffProd(a1, a2, b1, b2, q) returns $(a1\,a2 - b1\,b2)/q$. \end{retval}$

Manuel Bronstein 2000-12-13