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factorOfDeterminant


\begin{usage} factorOfDeterminant~a \end{usage}


Signature


\begin{params} {\em a} & M & A matrix\\ \end{params}

\begin{retval} Returns $(det?, d)$\ such that $d$\ is always a factor of the de... ...s exactly the determinant of $a$if $det?$\ is {\it true}\xspace . \end{retval}

\begin{remarks} $d$\ can also happen to be the determinant of $a$\ when $det?$\ is {\it false}\xspace , but the algorithm was unable to prove it. \end{remarks}


See Also


Manuel Bronstein 2000-12-13