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normalize


\begin{usage}
(a, B) := normalize~A
\end{usage}


Signature


\begin{params}
{\em A} & LR & An integral element\\
\end{params}

\begin{retval}
Returns $(a, B)$\ such that $A = a B$,
and $B$\ is a normalized rational element.
\end{retval}

\begin{remarks}
The normalization depends on the actual type LQ. For polynomial...
...icient if $1$, for vectors that the first
coordinate is $1$, etc.
\end{remarks}


Manuel Bronstein 2000-12-13