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makeIntegralBy


\begin{usage}
($\mu$, A) := makeIntegralBy~B
\end{usage}


Signature


\begin{params}
{\em B} & LQ & A rational element\\
\end{params}

\begin{retval}
Returns $(\mu, A)$\ such that $A = \mbox{shift}(B, \mu)$\ is integral.
\end{retval}


Manuel Bronstein 2000-12-13